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125=20x-x^2
We move all terms to the left:
125-(20x-x^2)=0
We get rid of parentheses
x^2-20x+125=0
a = 1; b = -20; c = +125;
Δ = b2-4ac
Δ = -202-4·1·125
Δ = -100
Delta is less than zero, so there is no solution for the equation
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